Divisibility Rule for 7 – 3 Different Methods Explained with Examples

Divisibility by 7 Rule

In this section, we’ll explore three methods:

  • The last-digit doubling method (best for smaller numbers)
  • The chunk (3-digit) alternating sum method (best for 5 digit or larger numbers)
  • Mod or remainder alternating sum method

A number is said to be divisible by 7 if it can be divided by 7 without leaving any remainder. Instead of performing long division every time, there is a shortcut rule:

Divisibility Rule for 7:
Take the last digit of the number, double it, and subtract this from the remaining leading part of the number.

  • If the result is divisible by 7 (or is 0), then the original number is divisible by 7.
  • Repeat the process if needed until you get a smaller number that you can easily check.

Step-by-Step Method

  1. Separate the last digit of the number.
  2. Double the last digit.
  3. Subtract this doubled value from the rest of the digits.
  4. Check divisibility of the new number by 7.
  5. Repeat until you reach a small enough number.

Examples of the Divisibility Rule for 7

Example 1: Check if 203 is divisible by 7

  1. Last digit = 3
  2. Double it = 6
  3. Remaining part = 20
  4. Subtract = 20 – 6 = 14
  5. 14 ÷ 7 = 2 (perfectly divisible)

Therefore, 203 is divisible by 7.

Example 2: Check if 371 is divisible by 7

  1. Last digit = 1
  2. Double it = 2
  3. Remaining part = 37
  4. Subtract = 37 – 2 = 35
  5. 35 ÷ 7 = 5 (perfectly divisible)

So, 371 is divisible by 7.

Example 3: Check if 422 is divisible by 7

  1. Last digit = 2
  2. Double it = 4
  3. Remaining part = 42
  4. Subtract = 42 – 4 = 38
  5. 38 ÷ 7 = 5 remainder 3 (not divisible)

Hence, 422 is not divisible by 7.


Shortcut Variations of the Rule

Apart from the standard method, there are two additional approaches to check divisibility by 7:

1. Repeated Subtraction Method

  • Keep subtracting 7 from the number until you reach 0 or a small remainder.
  • If the final result is 0, the number is divisible.

Example: 49 → 49 – 7 – 7 – 7 … = 0
Yes, Divisible by 7.

2. Direct Division Check (for small numbers)

For smaller numbers under 100, you can directly check with multiplication tables of 7:
7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98.

If the number is present in this list, it is divisible by 7.

When numbers reach 5 digits or more, you can use the 3-digit chunk and alternating sum rule. This approach uses modular arithmetic and works faster.

Rule:

  1. Split the number into 3-digit chunks ( Groups ) starting from the right.
  2. Assign alternating signs (+, –, +, – …), beginning with the rightmost chunk (Group) as positive.
  3. Add/subtract the chunks (Groups of 3 digits).
  4. If the result is divisible by 7, the original number is also divisible by 7.

(Tip: You can reduce each chunk modulo 7 before summing to keep numbers small.)


Example A: 987,654,321

Chunks ( Groups of 3 digits from right) → 321, 654, 987
Alternating sum → 321 – 654 + 987 = 654

Now you can apply last digit doubling method to 654

So we get 65-8 = 57 , which is not divisible by 7
So given number is not divisible by 7.


Example B: 557,664,184

Chunks → 184, 664, 557
Alternating sum → 184 – 664 + 557 = 77
Check → 77 ÷ 7 = 11
Divisible by 7.


Example: 666,142,778 (12-digit ready style)

Chunks → 778, 142, 666
Now reduce each chunk mod 7:

  • 778 mod 7 = 1 ( Remainder method )
  • 142 mod 7 = 2
  • 666 mod 7 = 1

Alternating sum → (1 – 2 + 1) = 0
Divisible by 7.


When to Use Which Method?

  • Numbers with up to 6 digits → Use the last-digit doubling & subtraction rule (quick and simple).
  • Numbers with 9 digits or more → Use the 3-digit chunk alternating sum method (saves time and avoids long calculations).

Both methods give the same result but choosing the right method makes checking divisibility much faster.


Key Takeaways

  • Divisibility by 7 is not as straightforward as 2, 3, or 5, but with these rules it becomes easy.
  • For small numbers, use the classic last-digit rule.
  • For very large numbers, break them into 3-digit chunks and use the alternating sum rule.
  • Practicing both methods will make you faster at solving math problems, whether in exams, mental math, or coding tasks.

Why is the Divisibility Rule for 7 Useful?

  • Saves time in competitive exams like SSC, Banking, and Olympiads.
  • Helps in quick factorization of larger numbers.
  • Useful in mental math and aptitude tests.

Quick Practice Questions

  1. Is 875 divisible by 7?
  2. Check whether 1197 is divisible by 7.
  3. Find if 2464 is divisible by 7.

(Try applying the rule step by step!)

When solving math problems, especially in number theory or competitive exams, checking whether a number is divisible by another saves time. While divisibility rules for numbers like 2, 3, 5, and 9 are straightforward, the divisibility rule for 7 often confuses students. We have broke it down step by step with clear methods, explanations, and examples.

The divisibility rule for 7 may seem tricky at first, but with practice, it becomes as simple as the rules for 3 or 9. By using the method of doubling the last digit and subtracting it, you can quickly determine whether a number is divisible by 7 without doing long division.